06-05-2014
Mathematics

Answered

Find the equation of the circle that satisfies the given conditions. Radius 2 and center (4, -7)?

Verified Answer :

Anonymous Anonymous

06-05-2014

\(The\ equation\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\\\\center:(a;\ b)\\\\radius:r\)

\(Center:(4;-7);\ radius:r=2\\\\(x-4)^2+(y+7)^2=2^2\\\\(x-4)^2+(y+7)^2=4\)

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