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\(\hbox{the sum identity:} \\ \sin(\alpha + \beta)= \sin \alpha \cos \beta + \sin \beta \cos \alpha \\ \\ \sin (90^\circ +q)= \\ \sin 90^\circ \cos q+ \sin q \cos 90^\circ= \\ 1 \times \cos q + \sin q \times 0= \\ \cos q\)

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Answer:

Option B is your answer

Step-by-step explanation:

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