Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum of two times the number of test tubes and five times the number of beakers is 450. If b is the number of beakers and t is the number of test tubes, the system of linear equations representing this situation is . The number of beakers in the school’s lab is , and the number of test tubes in the school’s lab is
b= number of beakers which there are 450
t= number of test tubes
the answer is 1.46
Answer:
Number of test tubes is 150 while the number of beakers is 30
Step-by-step explanation:
Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660.
The above expression can be expressed below
Let the number of test tubes = t
Let the number of beakers = b
5t - 3b = 660.......................(i)
The sum of two times the number of test tubes and five times the number of beakers is 450.
This can be expressed as follows
2t + 5b = 450..................(ii)
The linear equation is simultaneous equation
5t - 3b = 660.......................(i)
2t + 5b = 450..................(ii)
2t = 450 - 5b
t = 450/2 -5b/2
t = 225 - 5b/2
Insert t in equation (i)
5t - 3b = 660.......................(i)
5(225 - 5b/2) - 3b = 660
1125 - 25b/2 -3b = 660
1125- 660 = 12.5b + 3b
465 = 15.50b
465/15.50 = b
b = 30
insert b in equation (ii)
2t + 5b = 450..................(ii)
2t + 5(30) = 450
2t = 450 - 150
2t = 300
t = 300/2
t = 150
Number of test tubes is 150 while the number of beakers is 30