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You mean \(\dfrac{x-3}{2x-1}\), right?
So to find excluded value, you just set denominator equal to zero;
\(2x-1 = 0\)
From here, you just solve for x. Add both sides by 1 then divide both sides by 2, then you would have final answer;
\(\boxed{x=\dfrac{1}{2}}\)
So \(\frac{1}{2}\) is your excluded value.
