Quadrilateral ABCD has the following vertices.


A(-5, 5) B(4, 5) C(2, 0) D(-5, -2)


Determine the length of the sides of the quadrilateral, and arrange them in order from longest length to shortest length.

Verified Answer :

A(-5,5)
B(4,5)
C(2,0)
D(-5,-2)

AB,BC,CD,DA

AB = [4-(-5)),5-5]=[9,0]
Lenght  \(AB= \sqrt{9^2+0^2}= \sqrt{81} =9\)

BC = [2-4,0-5]=[-2,-5]
Lenght  \(BC=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}\)

CD = [-5-2,-2-0]=[-7,-2]
Lenght  \(CD=\sqrt{(-7)^2+(-2)^2}=\sqrt{49+4}=\sqrt{53}\)

DA =[-5-(-5),-2-5]=[0,-7]
Lenght \(DA=\sqrt{0^2+(-7)^2}=\sqrt{49}=7\)

sorted from longest to shortest:
AB, CD,DA,BC
\(\sqrt{81}, \sqrt{53}, \sqrt{49}, \sqrt{29}\)