The answer is B) (11,7) and (7,10)
First calculate the distance (d) between the points, using the formula:
d = √((y2 - y1)² + (x2 - x1)²)
A distance between points A (1,2) and B (5,-1) is:
d1 = √((-1 - 2)² + (5 - 1)²) = √((-3)² + (4)²) = √(9 + 16) = √25 = 5
So, we know that one side of the rectangle is 5 units. Using the known area of the rectangle, let's calculate the other side:
A = d1 d2
A = 50
d1 = 5
50 = 5 d2
d2 = 50/5
d2 = 10
We need to find slope between two points now:
m = (y2 - y1) / (x2 - x1) = (-1 - 2) / (5 - 1) = -3 / 4
Find the negative reciprocal slope:
m1 = -1/m = 4 / 3
Now, you want the points C and D 10 units (d2) away going at the slope m1:
Use the Pythagorean triple 3 : 4 : 5 to calculate sides, if hypotenuse is 10:
3 : 4 : 5 = a : b : 10
32 : 42 : 5*2 = 6 : 8 : 10
So, sides have length of 6 and 8.
Now, find possible points
A(1,2) ⇒ D(1 + 6, 2 + 8) or D(1 - 6, 2 - 8)
⇒ D(7, 10) or D(-5, -6)
B(5,-1) ⇒ C(5 + 6, -1 + 8) or C(5 - 6, -1 - 8)
⇒ C(11,7) or C(-1, -9)
Among all choices, the correct one is B) (11,7) and (7,10)
