how would you solve 3sin0=sin0-1
I would subtract 1sin(Θ) from each side of the equation.The equation would then say that 2sin(Θ) = -1 .I would only have to find angles whose sin is -1/2 ,and those would be my solutions.
3sinΘ = sinΘ - 13sinΘ - sinΘ = sinΘ - sinΘ - 1 2sinΘ = -1 2sin 2sin Θ = -2.864934497