The distance traveled by a falling rock is modeled by d=5t^2, where d is the distance in meters and t is the time in seconds. Write and simplify an expression for the distance the rock falls at 2t seconds. Is it twice as far? Explain your reasoning.
So given \(d=5t^2\), you need to substitute 2t as t, \(5(2t)^2\). Simplify the equation; \(5(4t^2)\) and then to \(20t^2\). when you plug in values for time, lets say 4, the distance traveled quadruples. \(d=5(4)^2\) \(d=80m\) \(d=5(20)^2\) \(d=320m\)
