Answered

A sequence has an initial value of 10 and each term is twice the previous term. Which function models this sequence?

1) a(n)=10(2)^n
2) a(n)=10(2)^n-1
3) a(n)=10+2n
4) a(n)=10+2(n-1)

Verified Answer :

mackiemesser

\(a(1)=10
a(2)=20
a(3)=40\)

Lets look at available choices:
1) \(a(n)=10(2)^n\)
\(a(1)=10*2=20\) wrong as a(1) should be 10
2) \(a(n)=10*2^{n-1}\) is the right choice because if you put 1 as n in the first case you will get:
\(a(1)=10*2^{1-1}=10*2^{0}=10*1\)
3) \(a(n)=10+2n\)
\(a(1)=10+2=12\) wrong as a(1) should be 10 
4) \(a(n)=10+2(n-1)\)
\(a(1)=10\) right but...
\(a(2)=10+2=12\) wrong as a(2) should be 20

3) and 4) can be dismissed, at once, because the is addition sign between them, and consecutive numbers should be multiplied.

In short 2) is the right answer



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