Which shows the equation below written in standard form?


9 - 7x = (4x - 3)2 + 5

A16x2 - 31x - 5 = 0
B16x2 - 31x + 5 = 0
C16x2 - 17x - 5 = 0
D16x2 - 17x + 5 = 0

Verified Answer :

naǫ

\(9-7x=(4x-3)^2+5 \\ 9-7x=16x^2-24x+9+5 \\ 9-7x=16x^2-24x+14 \\ 0=16x^2-24x+14-9+7x \\ 0=16x^2-17x+5 \\ \boxed{16x^2-17x+5=0} \\ \hbox{answer D}\)

Answer:

Option D - \(16x^2-17x + 5=0\)

Step-by-step explanation:

Given : Expression \(9 - 7x = (4x - 3)^2 + 5\)

To find : Which shows the equation below written in standard form?

Solution :

Step 1 - Write the expression

\(9 - 7x = (4x - 3)^2 + 5\)

Step 2 - Solve the square term

\(9 - 7x = 16x^2+9-24x + 5\)

Step 3 - Place like term together

\(16x^2-24x+7x + 5+9-9=0\)

\(16x^2-17x + 5=0\)

Therefore, Option D is correct.

The standard form of the equation is \(16x^2-17x + 5=0\)