mjchey
Answered

How many combinations of 3 students can a teacher choose from 32 students?   A. 96   B. 4960   C. 29,760   D. 32,768

Verified Answer :

\(\frac{32*31*30}{3*2*1}\)

The answer is:\(\frac{29760}{6}\) or \(4960\) 


marmal

\({32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960\)

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