what is the area of a rectangle with a length of (x^2-2) and a width of(2x-x+2)
The area of a rectangle can be found through the formula \(A=lw\), where l is the length and w is the height. In this situation, the answer can be found by multiplying the length and width provided:
\((x^2-2)*(2x-x+2)\)
The distributive property must be applied here:
\((x^2-2)*(2x-x+2) \\
2x^3-x^3+2x^2-4x+2x-4\)
Now simplify by combining like terms:
The area is
\(x^3+2x^2-2x-4\)
A = lw
A = (x² - 2)(2x - x + 2)
A = (x² - 2)(x + 2)
A = x²(x + 2) - 2(x + 2)
A = x²(x) + x²(2) - 2(x) - 2(2)
A = x³ + 2x² - 2x - 4