axis of symmetry for f(x) = -2x2 + 20x -42
For the function \(f(x)=2x^2 +20x-42\)We can use the formula for the axis of symetry, which is \(x= \frac{-b}{2a}\)With the values substituted, we get...\(\frac{-20}{2(-2)} =5\)Therefore the axis of symmetry is \(x=5\)
Answer: X=5
Step-by-step explanation:
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