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A rectangle has an area of 30 square units and a perimeter of 34 meters.what are the dimensions of this rectangle

Verified Answer :

Edmund

\(P=2L+2W\)
\(A=WL\)

Therefore, if \(P=34\), and \(A=30\), then let us find the factors of 30 that could give a sum of half of the perimeter which is 34. Therefore:

\(P=2*15+2*2\)
\(A=15*2\)

\(P=34\)
\(A=30\)

Therefore, the dimensions of this rectangle are 15 and 2.

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