a 16.0g sample of iron was heated from 0 degrees Celsius o 35.0 degrees Celsius.the iron absorbed 246.4J of energy as heat. what is the specific heat of this piece of iron?
Specific heat means the amount heat needed when unit mass of a substrate increase one degree of temperature. So the specific heat = the heat absorbed/(the mass of the substrate change in temperature) = 264.4/(1635)=0.472 J/(g*℃)
Answer: \(0.44J/g^0C\)
Explanation:
Specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of 1g of substance through \(1^0C\)
\(Q= m\times c\times \Delta T\)
Q= heat gained = 246.4 J
m= mass of the substance = 16 g
c = heat capacity of iron= ? J/g ° C
\(\Delta T={\text{Change in temperature}}=(35-0)^oC=35^0C\)
\(246.4=16g\times cJ/g^oC\times 35^oC\)
\(c=0.44J/g^0C\)
Thus specific heat capacity of iron is \(0.44J/g^0C\)