So,
There are 4 red marbles.
There are 7 blue marbles.
There are 5 green marbles.
There are 16 marbles in total.
a.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
\(\frac{4}{16} \ or\ \frac{1}{4}\)
Next, the probability of selecting a blue marble.
\(\frac{7}{16}\)
Multiply the probabilities together.
\(\frac{1}{4} * \frac{7}{16} = \frac{7}{64}\)
That is the probability for event a.
b.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
\(\frac{4}{16} \ or\ \frac{1}{4}\)
Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.
\(\frac{7}{15}\)
Multiply the probabilities together.
\(\frac{1}{4} * \frac{7}{15} = \frac{7}{60}\)
That is the probability for event b.
c.
Obviously:
\(\frac{7}{64}
eq \frac{7}{60}\)
So the answer is no.
