Verified Answer :

browntown5

All you gotta do is multiply the cm by 15,
For 13) you'd do \(2.5*15\)
14) \(0.2*15\) 
15) \(15*15\)
then for 16) \(4.6*15\)

calculista

Let

x-------> distance in the map in cm

y-------> actual distance in Km

we know that

\(Scale\ Map=\frac{x}{y} \\ \\ Scale\ Map=\frac{1}{15}\frac{cm}{Km}\)

so

\(\frac{x}{y}=\frac{1}{15}\)

\(y=15x\) --------> equation \(1\)

Part 13) find the actual distance corresponding to the scale map \(2.5\ cm\)

In this problem we have

\(x=2.5\ cm\)

Substitute the value of x in the equation  \(1\) to find the actual distance

\(y=15*2.5=37.5\ Km\)

therefore

the answer part 13) is

the actual distance is \(37.5\ Km\)

Part 14) find the actual distance corresponding to the scale map \(0.2\ cm\)

In this problem we have

\(x=0.2\ cm\)

Substitute the value of x in the equation  \(1\) to find the actual distance

\(y=15*0.2=3\ Km\)

therefore

the answer part 14) is

the actual distance is \(3\ Km\)

Part 15) find the actual distance corresponding to the scale map \(15\ cm\)

In this problem we have

\(x=15\ cm\)

Substitute the value of x in the equation  \(1\) to find the actual distance

\(y=15*15=225\ Km\)

therefore

the answer part 15) is

the actual distance is \(225\ Km\)

Part 16) find the actual distance corresponding to the scale map \(4.6\ cm\)

In this problem we have

\(x=4.6\ cm\)

Substitute the value of x in the equation  \(1\) to find the actual distance

\(y=15*4.6=69\ Km\)

therefore

the answer part 16

the actual distance is \(69\ Km\)

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