Verified Answer :
Answer: 21.3 km
Step-by-step explanation:
Given: On each of 3 days the distance traveled by Derrick to school = 6.45 km
The distance rode by Derrick to library = 150 meters
Since, 1 m=\(\frac{1}{1000}\ km\)
Thus, the distance rode by Derrick to library = \(150\times\frac{1}{1000}\ km=0.15\ km\)
The distance rode by Derrick to home = 500 meters.
Thus, the distance rode by Derrick to home = \(500\times\frac{1}{1000}\ km=0.5\ km\)
Distance he rode in each day = \(6.45+0.15+0.5=7.1\ km\)
Now, Distance he rode in 3 days = \(3\times7.1=21.3\ km\)
Answer:
21.3 km.
Step-by-step explanation:
On each of 3 days, Derrick rode 6.45 km to school, 150 meters to the library, and then 500 meters back home.
We know that
1 km = 1000 m
6.45 km = 6450
Total distance covered by Derrick in one day = 6450+150+500 meters
= 7100 meters
=7.1 kilometers
The distance covered by Derrick on each day is 7.1 km. So, the distance covered by Derrick in 3 days is
\(Total =3\times 7.1\)
\(Total =21.3\)
Therefore, Derrick rides 21.3 km for the 3 days altogether.