Can you please help me solve this equation (-3√7)²+(3√11)²?
(-3√7)^2= 97=63 when you raise to the second power, -3 becomes 9
and √7 becomes 7
(3√11)^2=911=99
99+63=162
\((-3\sqrt{7})^{2} + (3\sqrt{11})^{2} \\(-3\sqrt{7})(-3\sqrt{7}) + (3\sqrt{11})(3\sqrt{11}) \\9\sqrt{49} + 9\sqrt{121} \\9(7) + 9(11) \\63 + 99 \\162\)