Polar coordinates are written as the distance of the point to the origin and its angle of elevation around the unit cirlce.
Draw a right triangle with an angle of \(\frac{\pi}6\) and a hypotenuse with a length of 5.
You can use trigonometric ratios to find the legs of this triangle, which are the x and y coordinates of the point.
\(\cos=\frac{adj}{hyp} \\\\ \cos(\frac{\pi}6)=\frac{x}5 \\\\ \frac{\sqrt{3}}2=\frac{x}5 \\\\ \frac{5\sqrt{3}}2=x\)
As for y...
\(\sin=\frac{opp}{hyp}\\\\\sin(\frac{\pi}6) = \frac{y}5 \\\\ \frac{1}2=\frac{y}5 \\\\ \frac{5}2=y\)
\(\boxed{(\frac{5\sqrt{3}}2,\ \frac{5}2)}\)
