Answer: The ball will land at 19.6 m
Explanation:
To calculate the horizontal range of the ball, we use the formula:
\(R=\frac{v^2\sin 2\theta}{g}\)
where,
v = velocity of the ball = 14 m/s
\(\theta\) = angle at which the ball is thrown = 51°
g = acceleration due to gravity = \(9.8m/s^2\)
Putting values in above equation, we get:
\(R=\frac{(14)^2\times \sin (2\times 51)}{9.8}\\\\R=19.6m\)
Hence, the ball will land at 19.6 m
