expand and simplify (2+3i)(4-I)
\((2+3i)(4-i)=\\ 8-2i+12i+3=\\ 11+10i\)
(2 + 3i)(4 - i)8 - 2i + 12i - 3i²8 + 10i - 3(-1)8 + 10i + 38 + 3 + 10i11 + 10i