Solution:
We are given that
\(\frac{5}{6} - \frac{1}{3}n = p(5-2n) \\ \frac{5}{6} - \frac{1}{3}n = 5p-2pn\)
By our initial condition, 5p = \(\frac{5}{6}\) while -2pn = \(-\frac{1}{3}\).
\(5p = \frac{5}{ \frac{6}{5}} = \frac{5}{30}\\ p = \frac{1}{6} \\ \\ -2pn = -\frac{1}{3}n \\ p= \frac{1}{ \frac{3}{2}} = \frac{1}{6}\)
and we are done as \(\frac{5}{6} - \frac{1}{3}n = p(5-2n)\) ⇒ \(\frac{5}{6} - \frac{1}{3}n = \frac{5}{6} - \frac{1}{3}n\)
