Verified Answer :

A segment of a circle has a 120 arc and a chord of 8in. The area of the segment = (120/360) x 3.14 x 8^2 = 67 in^2

Answer:

\(A = 22.342\,in^{2}\)

Step-by-step explanation:

The radius of the circle is:

\(2\cdot r \cdot \cos 30^{\textdegree} = 8\,in\)

\(r = \frac{8\,in}{2\cdot \cos 30^{\textdegree}}\)

\(r \approx 4.619\,in\)

Finally, the area of the segment is:

\(A = \left(\frac{120^{\textdegree}}{360^{\textdegree}} \right)\cdot \pi \cdot (4.619\,in)^{2}\)

\(A = 22.342\,in^{2}\)