3x+2y=112x+5y=22 help ?
so assume that x=x and y=y in both equationsuse elimination3x+2y=112x+5y=22multiply first equation by -2 and multiply second equaiton by 3-6x-4y=-226x+15y=66add together0x+11y=4411y=44divide by 11y=4subsite3x+2y=113x+2(4)=113x+8=11subtract 83x=3divide by 3x=1x=1y=4in (x,y) form (1,4)