If a number that is 6 more than another unknown number and the sum of both number gives 22, translating the word problem into algebraic expressions, the numbers are calculated as: 8 and 14.
First thing to do is to translate the word problem into algebraic expressions.
The first number:
Let x represent the unknown number which is another number.
The second number:
6 more than another number (x) will be translated as x + 6
The sum of both numbers:
Their sum equals 22. Therefore, we would have the following equation,
x + (x + 6) = 22
\(x + x + 6 = 22\)
\(2x + 6 = 22\)
- Subtract 6 from each side
\(2x = 22 - 6\\\\2x = 16\)
x = 8
The first number is 8.
The second number would be:
x + 6
8 + 6 = 14
Therefore, if a number that is 6 more than another unknown number and the sum of both number gives 22, translating the word problem into algebraic expressions, the numbers are calculated as: 8 and 14.
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