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There are 4 red balls, 6 white balls, and 3 blue balls in a bag. If one ball is drawn from the bag at random, what is the probability that it is not white?

Verified Answer :

jclainwizard

7/13 13 balls total minus 6 for the white balls 7 /13 are not white

JeanaShupp

Answer: \(\dfrac{7}{13}\)

Step-by-step explanation:

Given: The total number of balls = \(4+6+3=13\)

The number of white balls = 6

The balls which are not white =  \(13-6=7\)

If one ball is drawn from the bag at random, the probability that it is not white is given by :-

\(\text{P(balls not white)}=\dfrac{\text{balls not white}}{\text{Total balls}}=\dfrac{7}{13}\)

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