\(4x-2y=48\\ \\ 2x+6y=-18\)
First we'll multiply the second equation by -2
\(-2\cdot (2x+6y)=-2\cdot -18\\ \\ -4x-12y=36\)
Now let's add the new equation and the first one.
\((4x-2y)+(-4x-12y)=48+36\\ \\ 4x-4x-2y-12y=48+36\\ \\ -14y=84\\ \\ y=\frac { 84 }{ -14 } \\ \\ y=-6\)
We found y's value. We'll plug it in one of the equations to find x's value.
\(y=-6\\ \\ 4x-2y=48\\ \\ 4x-2\cdot -6=48\\ \\ 4x+12=48\\ \\ 4x=48-12\\ \\ 4x=36\\ \\ x=\frac { 36 }{ 4 } \\ \\ x=9\)
Solution ;
(9, -6)
