Verified Answer :

\(\sqrt{ x^{2} } = / x /,\) where / x / is "the absolute value of x";
Then 
\(\sqrt{3 x^{2} } = \sqrt{3} / x / ;\)
In ihe same way, \(\sqrt{3 x^{4} } = \sqrt{3} / x^{2} / = \sqrt{3} x^{2} ,\)because \(x^{2} \geq 0 ;\);
The square root of (3x^2) times 3 times the square root of (3x^4) is 9 × \(/ x /\)×\(x^{2}\) ;But, for x > 0, | x | = x ; for x < 0, | x | = –x ;
Finally, The square root of (3x^2) times 3 times the square root of (3x^4) is 3\(x^{3}\), for \(x \geq 0\) and -3\(x^{3}\), for \(x\ \textless \ 0 .\)