Verified Answer :

TSO

Solve by substitution

\(\sf{y=-x-1}\)
\(\sf{y+x=3}\)

Just plug in y=-x-1 into y+x=3

So we get:

\(\sf{(-x-1)+x=3}\)

Simplify that:

\(\sf{-1=3}\)

And since that is not true, that means this system of equations has no solutions!

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