\(\sf{y=x-5}\)
\(\sf{3x+y=7}\)
Lets solve this by substitution.
Lets plug in y=x-5 into 3x+y=7
So:
\(\sf{y=x-5}\)
\(\sf{3x+y=7}\)
Plugging it in:
\(\sf{3x+(x-5)=7}\)
Solve for x by simplifying that:
\(\sf{3x+x-5=7}\)
\(\sf{4x-5=7}\)
Add 5 on both sides
\(\sf{4x=12}\)
Divide by 4 on both sides
\(\sf{x=3}\)
Now simply plug x=3 back into any equation and solve for y
So:
\(\sf{y=x-5}\)
\(\sf{y=3-5}\)
Simplify that:
\(\sf{y=-2}\)
So we are left with our final answer which is
\(\boxed{\bf{(3,-2)}}\)
