\(A=27 \ cm^2 \\ \\ d_{1}=3x , \ \ d_{2} = 2x \\ \\ S=\frac{1}{2}\cdot d_{1}\cdot d_{2}\\ \\27 = \frac{1}{2}\cdot 3x \cdot 2x \\ \\ 3x^2 = 27 \ \ /:3\)
\(x^2 = 9 \\ \\3x=x=\sqrt{9}\\ \\x=3 \ cm \\ \\ d_{1}=3x = 3*3 =9 \ cm \\ \\d_{2}=2x=2*3 = 6 \ cm \\ \\ Answer : \\ The \ length \ of \ the \ diagonal \ is: \ d_{1}= 9 \ cm \ and \ d_{2}= 6 \ cm\)
