Simplify the expression: 1/1+cot^2x
\(\frac{1}{1+ ctg^{2}x }\)=\(\frac{1}{1+ \frac{cos ^{2} x}{sin ^{2}x} } = \frac{1}{ \frac{sin ^{2}x+cos ^{2} x }{ sin^{2} x} }= \frac{sin ^{2} x}{sin ^{2}x+cos ^{2} x } =sin ^{2}x\)
Answer:C. Sin^2x
Step-by-step explanation:
