Which is an equation of the given line in standard form?


A.

–8x + 9y = 23


B.

–8x + 9y = –23


C.

–8x + 7y = 25


D.

–9x + 8y = –23

Which is an equation of the given line in standard form? A. 8x + 9y = 23 B. 8x + 9y = 23 C. 8x + 7y = 25 D. 9x + 8y = 23 class=

Verified Answer :

-8x+9y=23 -- y=8/9x+23/9

(-4,-1), (1/2,3)
(3--1)/(1/2--4)= 4/(4 1/2)=.888888889

So answer A because if you rearrange it in y=mx+b form you see it's y=8/9x+23/9. And using the two points provided you can subtract to find the slope which comes out to be 8/9 the only two answers with that are A and B, so eliminate C and D. Then you can easily tell by looking at the graph that the y-intercept is positive, thus answer A is the only answer that works.

Answer : The correct option is, (A) -8x + 9y = 23

Step-by-step explanation :

The general form for the formation of a linear equation is:

\((y-y_1)=m\times (x-x_1)\)          .............(1)

where,

x and y are the coordinates of x-axis and y-axis respectively.

m is slope of line.

First we have to calculate the slope of line.

Formula used :

\(m=\frac{(y_2-y_1)}{(x_2-x_1)}\)

Here,

\((x_1,y_1)=(-4,-1)\) and \((x_2,y_2)=(\frac{1}{2},3)\)

\(m=\frac{(3-(-1))}{(\frac{1}{2}-(-4))}\)

\(m=\frac{8}{9}\)

Now put the value of slope in equation 1, we get the linear equation.

\((y-y_1)=m\times (x-x_1)\)

\((y-(-1))=\frac{8}{9}\times (x-(-4))\)

\((y+1)=\frac{8}{9}\times (x+4)\)

\(9\times (y+1)=8\times (x+4)\)

\(9y+9=8x+32\)

\(9y=8x+32-9\)

\(9y=8x+23\)

\(9y-8x=23\)

From the given options we conclude that the option A is an equation of the given line in standard form.

Hence, the correct option is, (A) -8x + 9y = 23