16-04-2015
Mathematics

Answered

What is the product of \(k^{3} + 9k^{2} + 3\) and \(7k^{2} - 5\)?

Verified Answer :

16-04-2015

(k³+9k²+3)(7k²-5)=

=k³·7k²+k³ ·(-5)+9k² · 7k²+9k² ·(-5)+ 3· 7k²+3·(-5)=

=7k^5-5k³+63k^4-45k²+21k²-15=

=7k^5+63k^4-5k³-24k²-15

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