solve the equation 9x +6=3 what is x
\(9x+6=3\) /-6
\(9x=-3 \\ \\ x=- \frac{3}{9} ^{/3}=- \frac{1}{3}\)
\(\sf9x+6=3\)Subtract 6 to both sides:\(\sf9x=-3\)Divide 9 to both sides:\(\sf~x=-\dfrac{1}{3}\)
