log(x^2 +5x+16) = 1 solve for x
\(D:x^2+5x+16\ \textgreater \ 0\\ D:x\in\mathbb{R}\\\ \log(x^2+5x+16)=1\\ 10^1=x^2+5x+16\\ x^2+5x+6=0\\ x^2+2x+3x+6=0\\ x(x+2)+3(x+2)=0\\ (x+3)(x+2)=0\\ x=-3 \vee x=-2\)
