First of all you need a balanced equation:
2(C4H10) + 11(O2) ---> 10 (H2O) +8 (CO2)
Then, you convert the unit :
\(7.14 g C4H10\) x \(\frac{1mole C4H10}{58gC4H10}\)×\(\frac{10mole H2O}{2mole C4H10}\)×\(\frac{18g H2O}{1moleH2O}\)
The answer should be 11.1g
( I'm not 100% sure about it though)