So open up the attachement I have posted so that way you can go along with me better. :)
So if the exterior angle is 112, then \(\sf{180-112 = z}\)
So \(\sf{z=68}\)
So that means any answer choice that does not have 68 has to be gone. Unfortunately, all of them have 48 so we can't eliminate any.
Also, \(\sf{x+y=112}\) because x+y+z=180 but subtract the value of z which is 68 and we get that.
So that means that the other two angles in the answer choice should add upto 112.
A) 70+42 = 112
B) 30+82= 112
C) 60+52 = 112
D) 42+88 = 130
So D is the correct answer. Because it does not equal to 112
~After doing this I realized that there was an easier way~
Just add up all of the 3 angles in the answer choice to see if it equals to 180/
A) 68+70+42 = 180
B) 30+68+82 = 180
C) 68+60+52 = 180
D) 68+42+88 = 198
And 198 degrees in a triangle is not possible, so the answer is D.
\(\boxed{\sf{Answer~is~D~which~is~68,42,88}}\)
