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What is the point-slope form of the equation of a line that passes through the point (6, −8) and has a slope of −2?

A.y+8=2(x-6)


B.y+8=-2(x-6)


C.y-6=-2(x-8)


D.y-8=-2(x+6)

Verified Answer :

iGreen

y - y1 = m(x - x1)

Where 'y1' is the y-value of the point, 'x1' is the x-value of the point, and 'm' is the slope.

So in this case:

y1 = -8
x1 = 6
m = -2

Plug them in:

y - (-8) = -2(x - 6)

or

y + 8 = -2(x - 6)

TSO

Point slope form is:
\(\sf {y - y_1 = m(x - x_1)}\)

Where \(\sf{(x_1,y_1)}\) is the point and \(\sf{m}\) is the slope.

So from your question:

\(\sf{ x_1 = 6}\)
\(\sf{y_1 = -8}\)
 \(\sf{m = -2}\)

Plug them into the equation for point slope form:

\(\sf {y - y_1 = m(x - x_1)}\)

Becomes when you plug it in:

\(\sf{y-(-8) = -2(x - 6)}\)

And when you subtract a negative that becomes addition so:

\(\sf{y+ 8 = -2(x - 6)}\)

And that would correlate to answer choice \(\sf{\boxed{B}}\)

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