A 14-foot ladder is set up 4 feet from the base of the building. How far up the building does the ladder reach?
This problem creates a right Triangle
the building is one side and the 4ft is the other side
the ladder is the hypotenuse
apply the Pythagorean Theorem'a^2 + b^2= c^2
4^2 + b^2 = 14^2
16+ b^2= 195
b^2= 180
b= square root of 180
b= 6 square root of 5
or 13.42
The distance between the building and the top of the ladder is about 13.42 feet.
Important information:
We need to find the distance between the building and the top of the ladder.
Let \(x\) be the distance between the building and the top of the ladder. Then, using the Pythagoras theorem, we get
\(x^2+(4)^2=(14)^2\)
\(x^2=196-16\)
\(x=\sqrt{180}\)
\(x\approx 13.42\)
Therefore, the distance between the building and the top of the ladder is about 13.42 feet.
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