Solve system using eliminations2x+4y=222x-2y=-8
\(2x+4y=22 \\ 2x-2y=-8 \ \ \ |\times (-1) \\ \\ 2x+4y=22 \\ \underline{-2x+2y=8} \\ 2x-2x+4y+2y=22+8 \\ 6y=30 \ \ \ |\div 6 \\ y=5 \\ \\ 2x-2y=-8 \\ 2x-2 \times 5=-8 \\ 2x-10=-8 \ \ \ |+10 \\ 2x=2 \ \ \ |\div 2 \\ x=1 \\ \\ \boxed{(x,y)=(1,5)}\)
