So to solve your question, we can use this:
\(\sf{a(b-c) = ab-ac}\)
\(\sf{a(b+c) = ab+ac}\)
So then
\(\sf{-(6w-1)}\)
If we use the above formulas then:
\(\sf{-(6w-1) = -6w+1}\)
And for
\(\sf{3(w-4)}\)
We will get:
\(\sf{3(w-4) = 3w-3(4) =3w-12}\)
And to simplify
\(\sf{-(6w-1)+3(w-4)}\)
Since we already calculated the individual parts, not put them together, so:
\(\sf{-6w+1+3w-12}\)
Now we have to add the like terms which are -6w and 3w. And also 1 and -12.
Rearranging the terms, we get:
\(\sf{-6w+3w-12+1}\)
And \(\sf{-12+1=-11}\)
And also \(\sf{-6w+3w= w(-6+3) = w(-3) = -3w}\)
So combining that, we get:
\(\sf{-3w-11}\)
Which is your final answer :)
