07-04-2015
Mathematics

Answered

2x-8/x^2

what is the range of this function ?

Verified Answer :

Hippalectryon Hippalectryon

09-04-2015

The function is continuous for \(x>0\). It goes to \(-\infty\) when \(x\to0\) and it goes to \(+\infty\) when \(x\to+\infty\) hence its range is \(\Bbb{R}=(-\infty,+\infty)\)

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