Verified Answer :

Hippalectryon

\(\begin{cases}x_1&-3x_2=-5\\-3x_1&-x_2=5\end{cases}\\\begin{cases}3x_1&-9x_2=-15\\-3x_1&-x_2=5\end{cases}\\\begin{cases}&-10x_2=-10\\-3x_1&-x_2=5\end{cases}\\\begin{cases}&x_2=1\\-3x_1&-1=5\end{cases}\\\boxed{\begin{cases}x_2=1\\x_1=-2\end{cases}}\)

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