give the function f (x) =9x+7, find its inverse
\(f(x)=9x+7\\ y=9x+7\\ 9x=y-7\\ x=\dfrac{1}{9}y-\dfrac{7}{9}\\ f^{-1}(x)=\dfrac{1}{9}x-\dfrac{7}{9}\\\)
Applying it's definition, the inverse of the function f(x) = 9x + 7 is given by:
\(f^{-1}(x) = \frac{x - 7}{9}\)
Suppose we have a function y = f(x). To find the inverse function, we exchange x and y in the original function, then isolate f.
In this problem, the function is:
y = 9x + 7
Exchanging:
x = 9y + 7
Isolating y:
9y = x - 7
\(y = \frac{x - 7}{9}\)
\(f^{-1}(x) = \frac{x - 7}{9}\)
More can be learned about inverse functions at https://brainly.com/question/8824268
#SPJ2