\(x^2 + 2x - 2 = 0 \\ \\ a=1 , \ b=2 , \ c= -2\\ \\ \Delta = b^{2}-4ac = 2^{2}-4*1* (-2)= 4+8=12 \\ \\\sqrt{\Delta }=\1{12}= \sqrt{4*3}=2\sqrt{3}\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-2-2\sqrt{3}}{2}=\frac{2(-1-\sqrt{3})}{2} =-1-\sqrt{3} \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-2+2\sqrt{3}}{2}=\frac{2(-1+\sqrt{3})}{2} =-1+\sqrt{3}\)
