find the slope of the line that contains (1,6) and (10, -9).
m=\(\frac{y1-y2}{x1-x2}\) = \(\frac{6-(-9)}{1-10}= \frac{15}{-9}=- \frac{5}{3}\)
So,
To find the slope, simply subtract the given solutions and put them in the proper form.
10 - 1 = 9
-9 - 6 = -15
\(Slope = \frac{-15}{9} \ or\ \frac{-5}{3} \ or\ -\frac{5}{3}\)