How to change 3 7/8 into an improper fraction
\(3\dfrac{7}{8}=\dfrac{3\cdot8+7}{8}=\dfrac{31}{8}\)
3 7/8So we can use this \(a \frac{b}{c} = \frac{(a \times c) + b}{c}\)So we get\(3 \frac{7}{8} = \frac{(3 \times 8) + 7}{8}\)= \(\frac{24+7}{8} = \frac{31}{8}\)
