Verified Answer :
There are 54 fish in the tank. The difference between the fish he had and the fish he has now is 45 fish. 1/3=2/6 1/2=3/6. I converted so there is a common denominator. 2/6+3/6=5/6. That leaves 9 fish. 9 fish is 1/6. So if I multiply 9 by 5 that gives me the rest of the fish, which is 45. Then, I add that together to get 54.
Answer: Total fish are 27, difference is 18
Step-by-step explanation:
Given: one-third of the fish in Liam's fish tank were added today. Half of the other fish were a gift to Liam last week. the other 9 came from Liam's old fish tank.
To Find: Number of the fish in the tank, difference between the number of fish Liam had in his old tank and the number he has now.
Solution: Let the total fish in tank be = x
total fish added today = \(\frac{1}{3}\times \text{x}\)
Total fish left = \(\text{x}-\frac{1}{3}\text{x}\)= \(\frac{2}{3}\text{x}\)
Fish gifted to him last week = \(\frac{1}{2}\times\frac{2}{3}\times \text{x}\)
= \(\frac{1}{3}\text{x}\)
Fish left = \(\frac{2}{3}\text{x}\) - \(\frac{1}{3}\text{x}\)
\(\frac{1}{3}\text{x}\)
now,
fish left in the tank are =\(\frac{1}{3}\text{x}\)
fish from liam's old tank = 9 = fish left in the tank
\(\frac{1}{3}\text{x}\) = 9
\(\text{x}\)=\(27\)
Total fish in liam's new tank= \(27\)
difference between the number of fish Liam had in his old tank and the number he has now
= \(27-9=18\)
Total Fish in Liam's new tank are 27 and difference between the number of fish Liam had in his old tank and the number he has now is 18.